A particle moves on a rough horizontal ground with some initial velocity say v 0 . If 3/4 th of its kinetic energy is lost in friction in time t 0 . Then coefficient of friction between the particle and the ground is-
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
A
th energy is lost i.e. 
KE is left. Hence new velocity becomes 
under the retardation µg in time t 0 ,
= v 0 – µg t 0 ⇒ µ = 
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